Option 2 : 45°

**Concept:**

The angle subtended by an arc at the center of a circle is double that of the angle that the arc subtends at any other given point on the circle.

Angles which are opposite to equal sides are equal

Sum of all interior angles of a triangle is = 180°

**Calculations:**

In Δ AOB

OA = OB (Radii)

∠OAB = ∠OBA = 45° (angles which are opposite to equal sides are equal)

∠AOB = 180° - (45° + 45°)

∠AOB = 90°

Now we know that,

The angle subtended by an arc at the center of a circle is double that of the angle that the arc subtends at any other given point on the circle.

∴ ∠ACB = 45°

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